Struct slab::Slab [−][src]
pub struct Slab<T> { /* fields omitted */ }
Expand description
Pre-allocated storage for a uniform data type
See the module documentation for more details.
Implementations
Construct a new, empty Slab
.
The function does not allocate and the returned slab will have no
capacity until insert
is called or capacity is explicitly reserved.
Examples
let slab: Slab<i32> = Slab::new();
Construct a new, empty Slab
with the specified capacity.
The returned slab will be able to store exactly capacity
without
reallocating. If capacity
is 0, the slab will not allocate.
It is important to note that this function does not specify the length of the returned slab, but only the capacity. For an explanation of the difference between length and capacity, see Capacity and reallocation.
Examples
let mut slab = Slab::with_capacity(10);
// The slab contains no values, even though it has capacity for more
assert_eq!(slab.len(), 0);
// These are all done without reallocating...
for i in 0..10 {
slab.insert(i);
}
// ...but this may make the slab reallocate
slab.insert(11);
Return the number of values the slab can store without reallocating.
Examples
let slab: Slab<i32> = Slab::with_capacity(10);
assert_eq!(slab.capacity(), 10);
Reserve capacity for at least additional
more values to be stored
without allocating.
reserve
does nothing if the slab already has sufficient capacity for
additional
more values. If more capacity is required, a new segment of
memory will be allocated and all existing values will be copied into it.
As such, if the slab is already very large, a call to reserve
can end
up being expensive.
The slab may reserve more than additional
extra space in order to
avoid frequent reallocations. Use reserve_exact
instead to guarantee
that only the requested space is allocated.
Panics
Panics if the new capacity overflows usize
.
Examples
let mut slab = Slab::new();
slab.insert("hello");
slab.reserve(10);
assert!(slab.capacity() >= 11);
Reserve the minimum capacity required to store exactly additional
more values.
reserve_exact
does nothing if the slab already has sufficient capacity
for additional
more values. If more capacity is required, a new segment
of memory will be allocated and all existing values will be copied into
it. As such, if the slab is already very large, a call to reserve
can
end up being expensive.
Note that the allocator may give the slab more space than it requests.
Therefore capacity can not be relied upon to be precisely minimal.
Prefer reserve
if future insertions are expected.
Panics
Panics if the new capacity overflows usize
.
Examples
let mut slab = Slab::new();
slab.insert("hello");
slab.reserve_exact(10);
assert!(slab.capacity() >= 11);
Shrink the capacity of the slab as much as possible without invalidating keys.
Because values cannot be moved to a different index, the slab cannot shrink past any stored values. It will drop down as close as possible to the length but the allocator may still inform the underlying vector that there is space for a few more elements.
This function can take O(n) time even when the capacity cannot be reduced or the allocation is shrunk in place. Repeated calls run in O(1) though.
Examples
let mut slab = Slab::with_capacity(10);
for i in 0..3 {
slab.insert(i);
}
slab.shrink_to_fit();
assert!(slab.capacity() >= 3 && slab.capacity() < 10);
The slab cannot shrink past the last present value even if previous values are removed:
let mut slab = Slab::with_capacity(10);
for i in 0..4 {
slab.insert(i);
}
slab.remove(0);
slab.remove(3);
slab.shrink_to_fit();
assert!(slab.capacity() >= 3 && slab.capacity() < 10);
Reduce the capacity as much as possible, changing the key for elements when necessary.
To allow updating references to the elements which must be moved to a new key,
this function takes a closure which is called before moving each element.
The second and third parameters to the closure are the current key and
new key respectively.
In case changing the key for one element turns out not to be possible,
the move can be cancelled by returning false
from the closure.
In that case no further attempts at relocating elements is made.
If the closure unwinds, the slab will be left in a consistent state,
but the value that the closure panicked on might be removed.
Examples
let mut slab = Slab::with_capacity(10);
let a = slab.insert('a');
slab.insert('b');
slab.insert('c');
slab.remove(a);
slab.compact(|&mut value, from, to| {
assert_eq!((value, from, to), ('c', 2, 0));
true
});
assert!(slab.capacity() >= 2 && slab.capacity() < 10);
The value is not moved when the closure returns Err
:
let mut slab = Slab::with_capacity(100);
let a = slab.insert('a');
let b = slab.insert('b');
slab.remove(a);
slab.compact(|&mut value, from, to| false);
assert_eq!(slab.iter().next(), Some((b, &'b')));
Clear the slab of all values.
Examples
let mut slab = Slab::new();
for i in 0..3 {
slab.insert(i);
}
slab.clear();
assert!(slab.is_empty());
Return the number of stored values.
Examples
let mut slab = Slab::new();
for i in 0..3 {
slab.insert(i);
}
assert_eq!(3, slab.len());
Return true
if there are no values stored in the slab.
Examples
let mut slab = Slab::new();
assert!(slab.is_empty());
slab.insert(1);
assert!(!slab.is_empty());
Return an iterator over the slab.
This function should generally be avoided as it is not efficient. Iterators must iterate over every slot in the slab even if it is vacant. As such, a slab with a capacity of 1 million but only one stored value must still iterate the million slots.
Examples
let mut slab = Slab::new();
for i in 0..3 {
slab.insert(i);
}
let mut iterator = slab.iter();
assert_eq!(iterator.next(), Some((0, &0)));
assert_eq!(iterator.next(), Some((1, &1)));
assert_eq!(iterator.next(), Some((2, &2)));
assert_eq!(iterator.next(), None);
Return an iterator that allows modifying each value.
This function should generally be avoided as it is not efficient. Iterators must iterate over every slot in the slab even if it is vacant. As such, a slab with a capacity of 1 million but only one stored value must still iterate the million slots.
Examples
let mut slab = Slab::new();
let key1 = slab.insert(0);
let key2 = slab.insert(1);
for (key, val) in slab.iter_mut() {
if key == key1 {
*val += 2;
}
}
assert_eq!(slab[key1], 2);
assert_eq!(slab[key2], 1);
Return a reference to the value associated with the given key.
If the given key is not associated with a value, then None
is
returned.
Examples
let mut slab = Slab::new();
let key = slab.insert("hello");
assert_eq!(slab.get(key), Some(&"hello"));
assert_eq!(slab.get(123), None);
Return a mutable reference to the value associated with the given key.
If the given key is not associated with a value, then None
is
returned.
Examples
let mut slab = Slab::new();
let key = slab.insert("hello");
*slab.get_mut(key).unwrap() = "world";
assert_eq!(slab[key], "world");
assert_eq!(slab.get_mut(123), None);
Return two mutable references to the values associated with the two given keys simultaneously.
If any one of the given keys is not associated with a value, then None
is returned.
This function can be used to get two mutable references out of one slab, so that you can manipulate both of them at the same time, eg. swap them.
Examples
use std::mem;
let mut slab = Slab::new();
let key1 = slab.insert(1);
let key2 = slab.insert(2);
let (value1, value2) = slab.get2_mut(key1, key2).unwrap();
mem::swap(value1, value2);
assert_eq!(slab[key1], 2);
assert_eq!(slab[key2], 1);
Return a reference to the value associated with the given key without performing bounds checking.
For a safe alternative see get
.
This function should be used with care.
Safety
The key must be within bounds.
Examples
let mut slab = Slab::new();
let key = slab.insert(2);
unsafe {
assert_eq!(slab.get_unchecked(key), &2);
}
Return a mutable reference to the value associated with the given key without performing bounds checking.
For a safe alternative see get_mut
.
This function should be used with care.
Safety
The key must be within bounds.
Examples
let mut slab = Slab::new();
let key = slab.insert(2);
unsafe {
let val = slab.get_unchecked_mut(key);
*val = 13;
}
assert_eq!(slab[key], 13);
Return two mutable references to the values associated with the two given keys simultaneously without performing bounds checking and safety condition checking.
For a safe alternative see get2_mut
.
This function should be used with care.
Safety
- Both keys must be within bounds.
- The condition
key1 != key2
must hold.
Examples
use std::mem;
let mut slab = Slab::new();
let key1 = slab.insert(1);
let key2 = slab.insert(2);
let (value1, value2) = unsafe { slab.get2_unchecked_mut(key1, key2) };
mem::swap(value1, value2);
assert_eq!(slab[key1], 2);
assert_eq!(slab[key2], 1);
Get the key for an element in the slab.
The reference must point to an element owned by the slab. Otherwise this function will panic. This is a constant-time operation because the key can be calculated from the reference with pointer arithmetic.
Panics
This function will panic if the reference does not point to an element of the slab.
Examples
let mut slab = Slab::new();
let key = slab.insert(String::from("foo"));
let value = &slab[key];
assert_eq!(slab.key_of(value), key);
Values are not compared, so passing a reference to a different location will result in a panic:
let mut slab = Slab::new();
let key = slab.insert(0);
let bad = &0;
slab.key_of(bad); // this will panic
unreachable!();
Insert a value in the slab, returning key assigned to the value.
The returned key can later be used to retrieve or remove the value using indexed
lookup and remove
. Additional capacity is allocated if needed. See
Capacity and reallocation.
Panics
Panics if the number of elements in the vector overflows a usize
.
Examples
let mut slab = Slab::new();
let key = slab.insert("hello");
assert_eq!(slab[key], "hello");
Return a handle to a vacant entry allowing for further manipulation.
This function is useful when creating values that must contain their
slab key. The returned VacantEntry
reserves a slot in the slab and is
able to query the associated key.
Examples
let mut slab = Slab::new();
let hello = {
let entry = slab.vacant_entry();
let key = entry.key();
entry.insert((key, "hello"));
key
};
assert_eq!(hello, slab[hello].0);
assert_eq!("hello", slab[hello].1);
Tries to remove the value associated with the given key, returning the value if the key existed.
The key is then released and may be associated with future stored values.
Examples
let mut slab = Slab::new();
let hello = slab.insert("hello");
assert_eq!(slab.try_remove(hello), Some("hello"));
assert!(!slab.contains(hello));
Remove and return the value associated with the given key.
The key is then released and may be associated with future stored values.
Panics
Panics if key
is not associated with a value.
Examples
let mut slab = Slab::new();
let hello = slab.insert("hello");
assert_eq!(slab.remove(hello), "hello");
assert!(!slab.contains(hello));
Return true
if a value is associated with the given key.
Examples
let mut slab = Slab::new();
let hello = slab.insert("hello");
assert!(slab.contains(hello));
slab.remove(hello);
assert!(!slab.contains(hello));
Retain only the elements specified by the predicate.
In other words, remove all elements e
such that f(usize, &mut e)
returns false. This method operates in place and preserves the key
associated with the retained values.
Examples
let mut slab = Slab::new();
let k1 = slab.insert(0);
let k2 = slab.insert(1);
let k3 = slab.insert(2);
slab.retain(|key, val| key == k1 || *val == 1);
assert!(slab.contains(k1));
assert!(slab.contains(k2));
assert!(!slab.contains(k3));
assert_eq!(2, slab.len());
Return a draining iterator that removes all elements from the slab and yields the removed items.
Note: Elements are removed even if the iterator is only partially consumed or not consumed at all.
Examples
let mut slab = Slab::new();
let _ = slab.insert(0);
let _ = slab.insert(1);
let _ = slab.insert(2);
{
let mut drain = slab.drain();
assert_eq!(Some(0), drain.next());
assert_eq!(Some(1), drain.next());
assert_eq!(Some(2), drain.next());
assert_eq!(None, drain.next());
}
assert!(slab.is_empty());
Trait Implementations
Create a slab from an iterator of key-value pairs.
If the iterator produces duplicate keys, the previous value is replaced with the later one.
The keys does not need to be sorted beforehand, and this function always
takes O(n) time.
Note that the returned slab will use space proportional to the largest key,
so don’t use Slab
with untrusted keys.
Examples
let vec = vec![(2,'a'), (6,'b'), (7,'c')];
let slab = vec.into_iter().collect::<Slab<char>>();
assert_eq!(slab.len(), 3);
assert!(slab.capacity() >= 8);
assert_eq!(slab[2], 'a');
With duplicate and unsorted keys:
let vec = vec![(20,'a'), (10,'b'), (11,'c'), (10,'d')];
let slab = vec.into_iter().collect::<Slab<char>>();
assert_eq!(slab.len(), 3);
assert_eq!(slab[10], 'd');
Auto Trait Implementations
impl<T> RefUnwindSafe for Slab<T> where
T: RefUnwindSafe,
impl<T> UnwindSafe for Slab<T> where
T: UnwindSafe,
Blanket Implementations
Mutably borrows from an owned value. Read more